Optimal. Leaf size=516 \[ -\frac{i a^3 f \text{PolyLog}\left (2,-i e^{c+d x}\right )}{b^2 d^2 \left (a^2+b^2\right )}+\frac{i a^3 f \text{PolyLog}\left (2,i e^{c+d x}\right )}{b^2 d^2 \left (a^2+b^2\right )}+\frac{a^2 f \text{PolyLog}\left (2,-\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b d^2 \left (a^2+b^2\right )}+\frac{a^2 f \text{PolyLog}\left (2,-\frac{b e^{c+d x}}{\sqrt{a^2+b^2}+a}\right )}{b d^2 \left (a^2+b^2\right )}-\frac{a^2 f \text{PolyLog}\left (2,-e^{2 (c+d x)}\right )}{2 b d^2 \left (a^2+b^2\right )}+\frac{i a f \text{PolyLog}\left (2,-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a f \text{PolyLog}\left (2,i e^{c+d x}\right )}{b^2 d^2}+\frac{f \text{PolyLog}\left (2,-e^{2 (c+d x)}\right )}{2 b d^2}+\frac{a^2 (e+f x) \log \left (\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}+1\right )}{b d \left (a^2+b^2\right )}+\frac{a^2 (e+f x) \log \left (\frac{b e^{c+d x}}{\sqrt{a^2+b^2}+a}+1\right )}{b d \left (a^2+b^2\right )}-\frac{a^2 (e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d \left (a^2+b^2\right )}+\frac{2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d \left (a^2+b^2\right )}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d}-\frac{(e+f x)^2}{2 b f} \]
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Rubi [A] time = 0.775852, antiderivative size = 516, normalized size of antiderivative = 1., number of steps used = 30, number of rules used = 10, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {5581, 3718, 2190, 2279, 2391, 5567, 4180, 5573, 5561, 6742} \[ -\frac{i a^3 f \text{PolyLog}\left (2,-i e^{c+d x}\right )}{b^2 d^2 \left (a^2+b^2\right )}+\frac{i a^3 f \text{PolyLog}\left (2,i e^{c+d x}\right )}{b^2 d^2 \left (a^2+b^2\right )}+\frac{a^2 f \text{PolyLog}\left (2,-\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b d^2 \left (a^2+b^2\right )}+\frac{a^2 f \text{PolyLog}\left (2,-\frac{b e^{c+d x}}{\sqrt{a^2+b^2}+a}\right )}{b d^2 \left (a^2+b^2\right )}-\frac{a^2 f \text{PolyLog}\left (2,-e^{2 (c+d x)}\right )}{2 b d^2 \left (a^2+b^2\right )}+\frac{i a f \text{PolyLog}\left (2,-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a f \text{PolyLog}\left (2,i e^{c+d x}\right )}{b^2 d^2}+\frac{f \text{PolyLog}\left (2,-e^{2 (c+d x)}\right )}{2 b d^2}+\frac{a^2 (e+f x) \log \left (\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}+1\right )}{b d \left (a^2+b^2\right )}+\frac{a^2 (e+f x) \log \left (\frac{b e^{c+d x}}{\sqrt{a^2+b^2}+a}+1\right )}{b d \left (a^2+b^2\right )}-\frac{a^2 (e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d \left (a^2+b^2\right )}+\frac{2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d \left (a^2+b^2\right )}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{b d}-\frac{(e+f x)^2}{2 b f} \]
Antiderivative was successfully verified.
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Rule 5581
Rule 3718
Rule 2190
Rule 2279
Rule 2391
Rule 5567
Rule 4180
Rule 5573
Rule 5561
Rule 6742
Rubi steps
\begin{align*} \int \frac{(e+f x) \sinh (c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx &=\frac{\int (e+f x) \tanh (c+d x) \, dx}{b}-\frac{a \int \frac{(e+f x) \tanh (c+d x)}{a+b \sinh (c+d x)} \, dx}{b}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{a \int (e+f x) \text{sech}(c+d x) \, dx}{b^2}+\frac{a^2 \int \frac{(e+f x) \text{sech}(c+d x)}{a+b \sinh (c+d x)} \, dx}{b^2}+\frac{2 \int \frac{e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}} \, dx}{b}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac{a^2 \int \frac{(e+f x) \cosh (c+d x)}{a+b \sinh (c+d x)} \, dx}{a^2+b^2}+\frac{a^2 \int (e+f x) \text{sech}(c+d x) (a-b \sinh (c+d x)) \, dx}{b^2 \left (a^2+b^2\right )}+\frac{(i a f) \int \log \left (1-i e^{c+d x}\right ) \, dx}{b^2 d}-\frac{(i a f) \int \log \left (1+i e^{c+d x}\right ) \, dx}{b^2 d}-\frac{f \int \log \left (1+e^{2 (c+d x)}\right ) \, dx}{b d}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{a^2 (e+f x)^2}{2 b \left (a^2+b^2\right ) f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac{a^2 \int \frac{e^{c+d x} (e+f x)}{a-\sqrt{a^2+b^2}+b e^{c+d x}} \, dx}{a^2+b^2}+\frac{a^2 \int \frac{e^{c+d x} (e+f x)}{a+\sqrt{a^2+b^2}+b e^{c+d x}} \, dx}{a^2+b^2}+\frac{a^2 \int (a (e+f x) \text{sech}(c+d x)-b (e+f x) \tanh (c+d x)) \, dx}{b^2 \left (a^2+b^2\right )}+\frac{(i a f) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 d^2}-\frac{(i a f) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 d^2}-\frac{f \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{2 b d^2}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{a^2 (e+f x)^2}{2 b \left (a^2+b^2\right ) f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac{i a f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac{f \text{Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}+\frac{a^3 \int (e+f x) \text{sech}(c+d x) \, dx}{b^2 \left (a^2+b^2\right )}-\frac{a^2 \int (e+f x) \tanh (c+d x) \, dx}{b \left (a^2+b^2\right )}-\frac{\left (a^2 f\right ) \int \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right ) \, dx}{b \left (a^2+b^2\right ) d}-\frac{\left (a^2 f\right ) \int \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right ) \, dx}{b \left (a^2+b^2\right ) d}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}+\frac{i a f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac{f \text{Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}-\frac{\left (2 a^2\right ) \int \frac{e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}} \, dx}{b \left (a^2+b^2\right )}-\frac{\left (a^2 f\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{a-\sqrt{a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac{\left (a^2 f\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{a+\sqrt{a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x}\right )}{b \left (a^2+b^2\right ) d^2}-\frac{\left (i a^3 f\right ) \int \log \left (1-i e^{c+d x}\right ) \, dx}{b^2 \left (a^2+b^2\right ) d}+\frac{\left (i a^3 f\right ) \int \log \left (1+i e^{c+d x}\right ) \, dx}{b^2 \left (a^2+b^2\right ) d}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac{a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac{i a f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac{a^2 f \text{Li}_2\left (-\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac{a^2 f \text{Li}_2\left (-\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac{f \text{Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}-\frac{\left (i a^3 f\right ) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac{\left (i a^3 f\right ) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac{\left (a^2 f\right ) \int \log \left (1+e^{2 (c+d x)}\right ) \, dx}{b \left (a^2+b^2\right ) d}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac{a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac{i a f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a^3 f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}-\frac{i a f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac{i a^3 f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac{a^2 f \text{Li}_2\left (-\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac{a^2 f \text{Li}_2\left (-\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac{f \text{Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}+\frac{\left (a^2 f\right ) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{2 (c+d x)}\right )}{2 b \left (a^2+b^2\right ) d^2}\\ &=-\frac{(e+f x)^2}{2 b f}-\frac{2 a (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 d}+\frac{2 a^3 (e+f x) \tan ^{-1}\left (e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{a^2 (e+f x) \log \left (1+\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d}+\frac{(e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b d}-\frac{a^2 (e+f x) \log \left (1+e^{2 (c+d x)}\right )}{b \left (a^2+b^2\right ) d}+\frac{i a f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 d^2}-\frac{i a^3 f \text{Li}_2\left (-i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}-\frac{i a f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 d^2}+\frac{i a^3 f \text{Li}_2\left (i e^{c+d x}\right )}{b^2 \left (a^2+b^2\right ) d^2}+\frac{a^2 f \text{Li}_2\left (-\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac{a^2 f \text{Li}_2\left (-\frac{b e^{c+d x}}{a+\sqrt{a^2+b^2}}\right )}{b \left (a^2+b^2\right ) d^2}+\frac{f \text{Li}_2\left (-e^{2 (c+d x)}\right )}{2 b d^2}-\frac{a^2 f \text{Li}_2\left (-e^{2 (c+d x)}\right )}{2 b \left (a^2+b^2\right ) d^2}\\ \end{align*}
Mathematica [A] time = 2.87536, size = 438, normalized size = 0.85 \[ \frac{\frac{a^2 \left (f \text{PolyLog}\left (2,\frac{b e^{c+d x}}{\sqrt{a^2+b^2}-a}\right )+f \text{PolyLog}\left (2,-\frac{b e^{c+d x}}{\sqrt{a^2+b^2}+a}\right )+f (c+d x) \log \left (\frac{b e^{c+d x}}{a-\sqrt{a^2+b^2}}+1\right )+f (c+d x) \log \left (\frac{b e^{c+d x}}{\sqrt{a^2+b^2}+a}+1\right )+d e \log (a+b \sinh (c+d x))-c f \log (a+b \sinh (c+d x))-\frac{1}{2} f (c+d x)^2\right )}{b}+i a f \text{PolyLog}(2,-i (\sinh (c+d x)+\cosh (c+d x)))-i a f \text{PolyLog}(2,i (\sinh (c+d x)+\cosh (c+d x)))+\frac{1}{2} b f \text{PolyLog}(2,-\sinh (2 (c+d x))-\cosh (2 (c+d x)))-2 a d e \tan ^{-1}(\sinh (c+d x)+\cosh (c+d x))+2 a c f \tan ^{-1}(\sinh (c+d x)+\cosh (c+d x))-2 a f (c+d x) \tan ^{-1}(\sinh (c+d x)+\cosh (c+d x))-b d e (c+d x)+b d e \log (\sinh (2 (c+d x))+\cosh (2 (c+d x))+1)-\frac{1}{2} b f (c+d x)^2+b c f (c+d x)-b c f \log (\sinh (2 (c+d x))+\cosh (2 (c+d x))+1)+b f (c+d x) \log (\sinh (2 (c+d x))+\cosh (2 (c+d x))+1)}{d^2 \left (a^2+b^2\right )} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.225, size = 3882, normalized size = 7.5 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{2} \, f{\left (\frac{x^{2}}{b} - \int -\frac{4 \,{\left (a^{3} x e^{\left (d x + c\right )} - a^{2} b x\right )}}{a^{2} b^{2} + b^{4} -{\left (a^{2} b^{2} e^{\left (2 \, c\right )} + b^{4} e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )} - 2 \,{\left (a^{3} b e^{c} + a b^{3} e^{c}\right )} e^{\left (d x\right )}}\,{d x} - \int \frac{4 \,{\left (a x e^{\left (d x + c\right )} + b x\right )}}{a^{2} + b^{2} +{\left (a^{2} e^{\left (2 \, c\right )} + b^{2} e^{\left (2 \, c\right )}\right )} e^{\left (2 \, d x\right )}}\,{d x}\right )} + e{\left (\frac{a^{2} \log \left (-2 \, a e^{\left (-d x - c\right )} + b e^{\left (-2 \, d x - 2 \, c\right )} - b\right )}{{\left (a^{2} b + b^{3}\right )} d} + \frac{2 \, a \arctan \left (e^{\left (-d x - c\right )}\right )}{{\left (a^{2} + b^{2}\right )} d} + \frac{b \log \left (e^{\left (-2 \, d x - 2 \, c\right )} + 1\right )}{{\left (a^{2} + b^{2}\right )} d} + \frac{d x + c}{b d}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.5035, size = 1767, normalized size = 3.42 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e + f x\right ) \sinh{\left (c + d x \right )} \tanh{\left (c + d x \right )}}{a + b \sinh{\left (c + d x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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